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The value of cos 2a/(1 - sin 2a) is01tan atan(45° + a) |
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Answer» COT( A - B) Now, LHS = cot( 45 - A) = = ( CotAcot45° + 1)/( cotA - cot45) = ( CotA +1)/( cotA - 1) = ( CosA/sinA +1)/( cosA/sinA - 1) = (CosA+sinA)?/(cosA+sinA)(COSA-sinA) = (cos?A+sin A+2sinAcosA)/(cos A-sin? A) = (1 + 2sinAcosA) / cos2A = (1 + sin2A ) /cos2A I hope this helps you:) if found HELPFUL mark it as brainiliest and follow plz |
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