The value of (3⋅2⋅1P0−4⋅3⋅2P1+5⋅4⋅3P2−⋯upto 101 term – InterviewSolution

1.	The value of (3⋅2⋅1P0−4⋅3⋅2P1+5⋅4⋅3P2−⋯upto 101 terms) +(2!−3!+4!−⋯upto 101 terms) is equal to
Answer» The value of $(3 \cdot 2 \cdot^{1} P_{0} - 4 \cdot 3 \cdot^{2} P_{1} + 5 \cdot 4 \cdot^{3} P_{2} - \dots upto 101 terms)$ $+ (2! - 3! + 4! - \dots upto 101 terms)$ is equal to

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