Saved Bookmarks
| 1. |
The value of `[(0.16)^(log_(2.5)(1/3+1/3^2+1/3^3+….+oo))]^(1/2)` isA. `1`B. `2`C. `3`D. `-1` |
|
Answer» Correct Answer - A If a quadratic………… `0.16^(log_(2.5((1)/(3)+(1)/(3^(2))+(1)/(3^(2))+...oo)))` `= 0.16^(log_(2.5(((1)/(3))/(1-(1)/(3)))))=0.16^(log_(2.5((1)/(2))))` `=0.16^(log_(2//5^(2)))= 1^(2) "root" = 4^((1)/(2))=2` "Roots are" `= 2, A` Sum of root `= 2+A=3` `implies A = 1` |
|