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The upwards normal force exerted by the force of an elevator on a passenger who weighs 600 N is 570 N. The acceleration of passanger isA. ZeroB. `1/2 m//s^(2) uarr`C. `1/2 m//s^(2) darr`D. `10 m//s^(2) darr` |
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Answer» Correct Answer - C Since, NgtW `:.` acceleration (a) is downwards Also N=m(g-a) `:. 570=60(g-a)` `rArr a=1/2 m//s^(2) (darr)` |
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