1.

The upwards normal force exerted by the force of an elevator on a passenger who weighs 600 N is 570 N. The acceleration of passanger isA. ZeroB. `1/2 m//s^(2) uarr`C. `1/2 m//s^(2) darr`D. `10 m//s^(2) darr`

Answer» Correct Answer - C
Since, NgtW
`:.` acceleration (a) is downwards
Also N=m(g-a)
`:. 570=60(g-a)`
`rArr a=1/2 m//s^(2) (darr)`


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