1.

The universal sets of sets a={x:x^2-5x+6=0} and b={x:x^2-3x+2=0} having least number of elements is​

Answer»

Step-by-step explanation:

GIVEN U={x∣x5−6x4+11x3−6x2=0}

x5−6x4+11x3−6x2=0

x2(x3−6x2+11x−6)=0

x2(x2−5x+6)(x−1)=0

x2(x−3)(x−2)(x−1)=0

Hence U={0,1,2,3}

A={x∣x2−5x+6=0}

x2−5x+6=0

(x−3)(x−2)=0

Hence A={2,3}

B={x∣x2−3x+2=0}

x2−3x+2=0

(x−2)(x−1)=0

B={1,2}

A∩B={2}


Discussion

No Comment Found

Related InterviewSolutions