The units digit of a two-digit number is 3 and seven times the sum of

1.	The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself. Find the number.
Answer» It is given that the units place digit is 3. So, let tens place digit be y. ∴ Our number = (10y + 3) …(1) Our given condition is that seven times the sum of the digits is the number itself. ∴ By given condition, 7(y + 3) = (10 y + 3) 7 y + 21 = 10 y + 3 ∴ 10 y - 7y = 21 - 3 ∴ 3 y = 18 ∴ y = 6 Substituting the value of y in equation1, Number = 10 × 6 + 3 = 63 Hence, required number is 63.

The units digit of a two-digit number is 3 and seven times the sum of the digits is the number itself. Find the number.

Answer»

It is given that the units place digit is 3.

So, let tens place digit be y.

∴ Our number = (10y + 3) …(1)

Our given condition is that seven times the sum of the digits is the number itself.

∴ By given condition,

7(y + 3) = (10 y + 3)

7 y + 21 = 10 y + 3

∴ 10 y - 7y = 21 - 3

∴ 3 y = 18

∴ y = 6

Substituting the value of y in equation1,

Number = 10 × 6 + 3 = 63

Hence, required number is 63.