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The units digit of a number is 3. The number is seven times the sum of its digits. Find the number |
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Answer» SOL: UNITS digit of a two digit NUMBER = 3 Let the tens digit of the number be x. Number = 10x + 3 Sum of the digits = (x + 3) Given that 7 TIMES the sum of the digits is the number itself. ⇒ 7(x + 3) = (10x + 3) ⇒ 7x + 21 = 10x + 3 ⇒ 10x - 7x = 21 - 3 ⇒ 3x = 18 ⇒ x = 6. Therefore, the digits in the tens PLACE is 6 and the number is 63. |
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