The unit vector parallel to the resultant of vectors a=4i+3j+6k and b=

1.	The unit vector parallel to the resultant of vectors a=4i+3j+6k and b=-i+3j-8k
Answer» Answer: (5i+6j-2k)÷√65 Step-by-step EXPLANATION: FIRST we have to find the resulting vector Resulting vector =a+b =(4i+3j+6k)+(i+3j-8k) =5i+6j-2k UNIT vector =given vector ÷(its MAGNITUDE) Magnitude=√x^2 +y^2 +z^2 Implies magnitude is√25+36+4 Which is√65 Therefore unit vector is (5i+6j-2k)÷√65

The unit vector parallel to the resultant of vectors a=4i+3j+6k and b=-i+3j-8k

Answer»

Answer:

(5i+6j-2k)÷√65

Step-by-step EXPLANATION:

FIRST we have to find the resulting vector

Resulting vector =a+b

=(4i+3j+6k)+(i+3j-8k)

=5i+6j-2k

UNIT vector =given vector ÷(its MAGNITUDE)

Magnitude=√x^2 +y^2 +z^2

Implies magnitude is√25+36+4

Which is√65

Therefore unit vector is (5i+6j-2k)÷√65

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The unit vector parallel to the resultant of vectors a=4i+3j+6k and b=-i+3j-8k​

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The unit vector parallel to the resultant of vectors a=4i+3j+6k and b=-i+3j-8k