The two vertices of equilateral triangle are (-2,0) and (2,0) find the

1.	The two vertices of equilateral triangle are (-2,0) and (2,0) find the third vertex
Answer» Let ABC be the ∆ then AB=AC=BC => AB^2= BC^2 = AC^2 .let x and y be the third vertex. AC^2 =AB^2.by distance formula (x+2)^2 +y^2 =(x-2)^2+y^2.x^2+4x+4=x^2-4x+4.8x=0x=0Now AB^2 =(2+2)^2+0 =16AB^2=AC^2 (0+2)^2+y^2 =16y^2=12. y=2√3. The third vertex =(0,2√3)

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