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The two ends of a rod of length `L` and a uniform cross-sectional area `A` are kept at two temperature `T_(1)` and `T_(2)` `(T_(1) gt T_(2))`. The rate of heat transfer. `(dQ)/(dt)`, through the rod in a steady state is given byA. `(dQ)/(dt)=(KL(T_(1)-T_(2)))/A`B. `(dQ)/(dt)=(K(T_(1)-T_(2)))/(LA)`C. `(dQ)/(dt)=KLA(T_(1)-T_(2))`D. `(dQ)/(dt)=(KA(T_(1)-T_(2)))/L` |
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Answer» Correct Answer - D For a rod of length L and area of cross-section A whose faces are maintained at temperature `T_(1)` and `T_(2)` respectively. Then in steady state the rate of heat flowing from one face to the other face in time t is given by `(dQ)/(dt)=(KA(T_(1)-T_(2)))/L` The curved surface of rod is kept insulated from surrounding to avoid leakage of heat |
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