1.

The two ends of a metal rod are maintained at temperatures 100^(@)C and 110^(@)C. The rate of heat flow in the rod is found to be 4.0" Js"^(-1). If the ends are maintained at temperatures 200^(@)C and 210^(@)C, the rate of heat flow will be :

Answer»

`16.8" Js"^(-1)`
`8.0" Js"^(-1)`
`4.0" Js"^(-1)`
`44.0" Js"^(-1)`

SOLUTION :From `H=kA((T_(1)-T_(2))/(L))`,
(i) `H_(1)kA((110-100)/(L))`
`H_(1)=10(kA)/(L)`
(ii) `H_(2)=kA((210-20)/(L))=10(kA)/(L)`
`:.H_(1)=H_(2)`
`:." Js"^(-1)=H_(2)`


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