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The transfer ration of a transistor is `50`. The input resistance of the transistor when used in the common -emitter configuration is `1 kOmega`. The peak value for an `A.C.` input voltage of `0.01 V` peak isA. `0.25 muA`B. `0.01 muA`C. `500 muA`D. `100 muA` |
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Answer» Correct Answer - c Input current `=(V_(i))/(R_(i))=(0.01)/(10^(3))= 10^(-5)A` Output collector current `=Bxx "input current"` `= 50xx10^(-5)` `=500A` |
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