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The trajectory of a projectile in a vertical plane is, y=αx−βx2, where α,β are constants, x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection and the maximum height attained are respectively given by : |
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Answer» The trajectory of a projectile in a vertical plane is, y=αx−βx2, where α,β are constants, x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection and the maximum height attained are respectively given by : |
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