The trajectory of a projectile in a vertical plane is: y=ax−bx2,where a and b are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The maximum height attained is

The trajectory of a projectile in a vertical plane is: y=ax−bx2,wher

1.	The trajectory of a projectile in a vertical plane is: y=ax−bx2,where a and b are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The maximum height attained is
Answer» The trajectory of a projectile in a vertical plane is: $y = a x - b x^{2}$ , where $a$ and $b$ are constants and $x$ and $y$ are respectively the horizontal and vertical distances of the projectile from the point of projection. The maximum height attained is

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The trajectory of a projectile in a vertical plane is: y=ax−bx2,where a and b are constants and x and y are respectively the horizontal and vertical distances of the projectile from the point of projection. The maximum height attained is

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