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the total pressure exerted by the mixture of equal moles of two gases is 5*10³ Nm-²in a container of volume 2 litres at 273k. calculate the number of moles of the gases mixed |
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Answer» ate,● Answer-0.0022 moles of each gas0.0044 moles for mixture● Explanation-# Given-P = 5×10^3 PAV = 2 L = 2×10^-3 m^3T = 273 K# Solution-Let n be total no of moles of mixture.According to IDEAL gas EQUATION,PV = nRT5×10^3 × 2×10^-3 = n × 8.314 × 273n = 10 / (8.314×273)n = 0.0044No of moles of each gas will be half i.e. 0.0044/2 = 0.0022 moles.Hope this HELPS... |
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