The total power dissipated in watts in the circuit shown here is A. 16

1.	The total power dissipated in watts in the circuit shown here is A. 16B. 40C. 54D. 4
Answer» Correct Answer - C (c ) The resistance of `6 Omega` and `3 Omega` are in parallel in the given circuit, their equivalent resistance is `(1)/(R_(1)) = (1)/(6) + (1)/(3) = (1 + 2)/(6) = (1)/(2)` or `R_(1) = 2 Omega` Again, `R_(1)` is in series with `4 Omega` resistance, hence ltbgt `R = R_(1) + 4 = 2 + 4 = 6 Omega` Thus, the total power dissipatesin the circuit `P = (V^(2))/(R )` Here, `V = 18 V, R = 6 Omega` Thus, `P = ((18)^(2))/(6) = 54 W`

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The total power dissipated in watts in the circuit shown here is A. 16B. 40C. 54D. 4

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