The total power dissipated in watts in the circuit shown here is A. 4W

1.	The total power dissipated in watts in the circuit shown here is A. 4WB. 16 WC. 40 WD. 54 W
Answer» Correct Answer - D The resistance of `6 Omega` and `3 Omega` are in parallel in the given circuit, their equivalent resistance is `1/(R_(1))=1/6+1/3=(1+2)/6=1/2` or `R_(1)=2Omega` Again `R_(1)` is in series with `4 Omega` resistance hence `R=R_(1)+4=2+4 =6Omega` Thus, the total dissipated in the circuit `p=(V^(2))/R` Here `V=18 V, R=6 Omega` Thus, `p=((18)^(2))/6=54W`

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The total power dissipated in watts in the circuit shown here is A. 4WB. 16 WC. 40 WD. 54 W

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