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The total number of ions present in 1 ml of 0.1M barium nitrate solution is :-A. `6.02xx10^(18)`B. `6.02xx10^(19)`C. `3.0xx6.02xx10^(19)`D. `3.0xx6.02xx10^(18)` |
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Answer» Correct Answer - C 1 mol Ba `(NO_(3))_(2)` contain ` to` 3 mole ions `n_(Ba)(NO_(3))_(2) =(0.1xx1)/(1000) =10 ^(-4)` NO. of ions `= 3xx10^(-4)xx6.02xx10^(23)` `3xx6.02xx10^(19)` |
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