The total distance between fourconsecutive crests of a transverse wave

1.	The total distance between fourconsecutive crests of a transverse waveis 6m. What is the wavelength of thewave.
Answer» ANSWER: The distance between two SUCCESSIVE crests is 1 1 wavelength,λ λ . Thus in a time of 1 1 period, the wave will travel 1 1 wavelength in distance. Thus the speed of the wave, V v , is: v= distance travelled time taken = λ T v=distance travelledtime taken=λT However,f= 1 T f=1T . Therefore, we can also write: v = λ T =λ⋅ 1 T =λ⋅f v=λT=λ⋅1T=λ⋅f We CALL this equation the wave equation. To summarise, we have that v=λ⋅f v=λ⋅f where v= v= speed in m⋅s −1 m·s−1 λ= λ= wavelength in m m f= f= frequency in Hz Hz Wave equation: v=f⋅λ v=f⋅λ or v= λ T v=λT

The total distance between fourconsecutive crests of a transverse waveis 6m. What is the wavelength of thewave.

Answer»

The distance between two SUCCESSIVE crests is 1

wavelength,λ

. Thus in a time of 1

period, the wave will travel 1

wavelength in distance. Thus the speed of the wave,

, is:

v= distance travelled

time taken =

v=distance travelledtime taken=λT

However,f=

f=1T

. Therefore, we can also write:

=λ⋅

=λ⋅f

v=λT=λ⋅1T=λ⋅f

We CALL this equation the wave equation. To summarise, we have that

v=λ⋅f

where

speed in

m⋅s −1

m·s−1

λ=

wavelength in m

frequency in Hz

Wave equation:

v=f⋅λ

v=λT