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the tip of a drawing pin has an area of 0.01 mm². Find the pressure exerted by it if a force of 20 N is applied by it. |
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Answer» Explanation: Area = 0.01 mm² = 1×10^-2 mm² = 1×10^-5= 1×10^-5 m²FORCE = 20 NWe know that,Pressure = Force / Area==> 20 / 1 × 10^-5m==> 20×10^5 PascalThus, the Pressure acting on the GIVEN area is 20 × 10^5 PaIf you think I was right surely mark it as BRAINLIEST ANSWER |
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