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The time taken for 10% completion of a first order reaction is 20 min . Then for 19% completion the reaction will take : |
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Answer» 40 MINS `k = (2.303)/(x) "log" (100)/(81)` since (i) = (II) `(2.303)/(20)"log" (100)/(90) = (2.303)/(x) "log" (100)/(81)` `x= (20 "log"(100)/(81))/("log" (100)/(90))` `= (20xx0.0915)/(0.046) = 40 ` min |
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