1.

The time taken by a radiowavw to go and come back after reflection from a communication satellite is

Answer»

`(1)/(4)`s
`(1)/(2)` s
1s
`(1)/(8)` s

Solution :`t=(2S)/(c )=(2xx36000km)/(3xx10^(5)KM//s)`, where height of the SATELLITE above the EARTH is 36000 Km and `c=3xx10^(8)m//s=3xx10^(5)km//s`.
`=(72)/(300)=((1)/(4))s`


Discussion

No Comment Found