The time taken by a particle performing shm to pass from point a to b where its velocities are same is 2s. After another 2s it returns to b. The ratio of distance ob to its amplitude

The time taken by a particle performing shm to pass from point a to b

1.	The time taken by a particle performing shm to pass from point a to b where its velocities are same is 2s. After another 2s it returns to b. The ratio of distance ob to its amplitude
Answer» r,● Answer-OB/A = 1/√2● Explaination-[REFER to the figure]Time period is -T = 2×4 T = 8 sTo SOLVE this,OB = Asin(wt)OB/A = sin(2πt/T)OB/A = sin(2π×1/8)OB/A = 1/√2Therefore, RATIO of DISTANCE OB to A is 1/√2 .Hope this helps you...

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The time taken by a particle performing shm to pass from point a to b where its velocities are same is 2s. After another 2s it returns to b. The ratio of distance ob to its amplitude

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