The time period of simple pendulum at the surface of earth is T. If it is taken to a height equal to the radius of earth. Find the period of new oscillations

The time period of simple pendulum at the surface of earth is T. If it

1.	The time period of simple pendulum at the surface of earth is T. If it is taken to a height equal to the radius of earth. Find the period of new oscillations
Answer» Solution :At a HEIGHT R new `G^(1)+(GM)/(r^(2))=(GM)/((2R)^(2))=g/4:.Tprop1/(SQRT(g))` `(T^(1))/(T_(0))=sqrt(g/(g_(1)))=sqrt(g/(g/4))=2` (or) `T^(1)=2T_(0)`