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The time period of revolution in the `3^(rd)` orbit of `Li^(2+)` ion is x sec. The time period of revolution in the `2^(nd)` orbit of `He^(+) ion, should beA. x secB. `3/2 x sec`C. `2/3 x sec`D. `8/27 x sec` |
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Answer» Correct Answer - 3 `Talpha (n^(3))/(Z^(2))` `x/y=9/3xx(2^(2))/(2^(3))` `y=2/3 x sec` |
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