1.

The time period of a large fluid star may depends upon its mean radius R, its mean density (p) and the gravitation constant G. Using dimensional consideration the value of T is :

Answer»

`kpRG`
`kp^(1/2)G^(1/2)`
`kp^(1/2)G^(-1/2)R^(0)`
`kp^(1/2)G^(-1)R^(0)`

Solution :Here `M^(0)L^(0)T^(1)=R^(x)p^(y)G^(Z)`
`=[L^(1)]^(x)[ML^(-3)]^(y)[M^(-1)L^(3)T^(-2)]^(z)`
`M^(y-z)L^(x-3y+3z)T^(-2z)`
`:.y-z=0` Solving we get
`-2z=1x=0,y=-(1)/(2),z=-(1)/(2)`
`x-3y+3z=0`
HENCE correct choice is `(C )`.


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