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The time of reverberation of a room a is one seond. What will be the time of reverberation of room having all the dimensions double of those of room A : |
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Answer» 1 s Where `alpha` is average absorption coefficient and S is surface area. `RARR T prop `V/S `THEREFORE (T_(1))/(T_(2)) = (V_(1))/(V_(2)) XX (S_(2))/(S_(1)) = (V)/(8V) xx (4S)/(S) = (1)/(2) ` `rArr T_(2) = 2T_(1) = 2xx 1 = 2s` correct choice is (b). |
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