The thermal conductance (reciprocal of the thermal resistance) for axi – InterviewSolution

1.	The thermal conductance (reciprocal of the thermal resistance) for axial flow of a truncated cone of length l is πK(r1r2)ln2. If the radius at the two ends of the cone are r1 and r2 and thermal conductivity of the material is K, then the value of n2 is
Answer» The thermal conductance (reciprocal of the thermal resistance) for axial flow of a truncated cone of length $l$ is $\frac{π K (r_{1} r_{2})}{l} n^{2}$ . If the radius at the two ends of the cone are $r_{1}$ and $r_{2}$ and thermal conductivity of the material is $K$ , then the value of $n^{2}$ is

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