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The tenth term of an AP is 30 and the eleventh term is 50. Find the AP. |
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Answer» Answer: Given: 6th term A6= 20, 11th term A11=30 we have, An= A1+(n-1)d => A6=A1+(6–1)d => 20=A1+5d ——equation (1) A11=A1+(11–1)d => 30=A1+(11–1)d => 30= A1+10d ——equation (2) equating 1 and 2, we have => d=2, substitute in eq(1) => 20= A1+5(2) =>A1=20–10=10 Hence, the FIRST term A1=10 and common difference d=2. Step-by-step explanation: |
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