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The tension in a string holding a solid block below the surface of a liquid (of density greater than that of solid) as shown in figure is `T_(0)` when the system is at rest. What will be the tension in the string if the system has an upward acceleration a? .A. `T(1-a/g)`B. `T(1+a/g)`C. `T(a/g-1)`D. `a/gT` |
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Answer» Correct Answer - B Let `v` be the volume of the solid block of density `rho.` Let `rho_(1)` be the density of water.Weight of body `=vrhog`. When the body is immersed in water. Tension in the string`=` Upward thrust `-` Weight of the body `implies T=vrho_(1)g-vrhog=vg(rho_(1)-rho_(2))` When the lift is moving upwards with acceleration a the tension in the string is `T=v(rho_(1)-rho)(g+a)` From eqn i and ii `T=T_(0)(1+a/g)` |
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