1.

The tens digit of a 2-digit number is less than the ones digit by 3. If the digits are reversed, thedifference between the two numbers is 27. If the sum of the digits is 11, find the numbers.

Answer»

LetXXbe the1s1sdigit of a number,X−3X−3is the10s10sdigit,

The number is10(X−3)+X10(X−3)+X.

Reverse the number soX−3X−3is1s1sdigit andXXis10s10sdigits,

Number becomes10(X)+(X−3)10(X)+(X−3)

The SUM of digits is1111hence

X+(X−3)=11X+(X−3)=11

2X=142X=14

X=7X=7

10s10sdigit=4digit=4,1s1sdigit=7digit=7,the number is 47.

The reverse is7474, and74−47=2774−47=27istrue.



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