The temperatures of the source and the sink of a Carnot engine are 500 K and 300 K respectively. If the temperature of the source diminished to 450 K, what will be the percentage change in efficiency?

The temperatures of the source and the sink of a Carnot engine are 500

1.	The temperatures of the source and the sink of a Carnot engine are 500 K and 300 K respectively. If the temperature of the source diminished to 450 K, what will be the percentage change in efficiency?
Answer» Solution :In the first CASE, EFFICIENCY `eta_(1) = 1 - (T_2)/(T_1) = 1 - (300)/(500) = 2/5` In the second case, efficiency `eta_(2) = 1-(T_2)/(T_1) = 1 - (300)/(450) = 1/3` `:.` Fractional change in efficiency `=(eta_(2) - eta_(1))/(eta_1) = (eta_2)/(eta_1)-1 = (1//3)/(2//5)-1 = 5/6-1 = -1/6` `:.` PERCENTAGE change = `-1/6 xx 100 = -16.67%` So, efficiency decreases by 16.67%.