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The temperature of a perfect black body is 1000 K and its area is 0.1 m^(2). If sigma=5.67xx19^(-8)Wm^(-2)K^(-4) calculate the heat radiated by it in 1 minute? |
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Answer» Solution :According to Stefan.s LAW if E is the energy RADIATED in 1 SEC by unit surface area then `E=sigmaT^(4)` `therefore` Total energy radiated, `E=A(sigmaT^(4))` `t=0.1xx5.67xx10^(-8)xx1000^(4)xx60` = `34.02xx10^(4)J` |
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