The temperature of 20 g of oxygen gas is raised from 50^(@)C to 100^(@)C. (i) At constant volume. Find out the amount of heat supplied and the rise in internalenergy in case. Given , R = 2 cal cdot mol^(-1) cdot K^(-1) , for oxygen, c_(v) = 0.155 cal cdot g^(-1) cdot^(@)C^(-1).

The temperature of 20 g of oxygen gas is raised from 50^(@)C to 100^(@

1.	The temperature of 20 g of oxygen gas is raised from 50^(@)C to 100^(@)C. (i) At constant volume. Find out the amount of heat supplied and the rise in internalenergy in case. Given , R = 2 cal cdot mol^(-1) cdot K^(-1) , for oxygen, c_(v) = 0.155 cal cdot g^(-1) cdot^(@)C^(-1).
Answer» Solution :HEAT supplied at constant VOLUME, `Q_(v) = mc_(v) (t_(f) - t_(i))` `=20 xx 0.155 xx (100-50) = 155 cal` Work done, W = 0 So, rise in internal ENERGY , `U_(f) - U_(i) = Q - W = 155 - 0 = 155 cal` `= 155 xx 4.2 J = 651 J`.