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The temperature-entropy diagram of a reversible engine cycle is given in figure. What is its efficiency? |
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Answer» Solution :Entropy CHANGE `=int_(A)^(B)(dQ)/T""T(S-S_(0))=Q` `Q_(1)=T_(0)S_(0)+1/2T_(0)S_(0)=3/2T_(0)S_(0)` : `Q_(2)=T_(0)(2S_(0)-S_(0))=T_(0)S_(0),""Q_(3)=0` `n=W/Q_(1)=(Q_(1)-Q_(2))/Q_(1)=1-Q_(2)/Q_(1)=1-(T_(0)S_(0))/(3/2T_(0)S_(0))=1/3` |
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