1.

The temperature co-effcient of resistance of a wire is `0.00125^(@)C.` At 500 K, its resistance is `1Omega.` The resistance of the wire will be `2Omega` atA. 1154 KB. 1100 KC. 1400 KD. 1127 K

Answer» Correct Answer - D
`1Omega=R_(2T)=R_(o)(1+alpha2T)...(i)`
`2Omega=R_(2T)=R_(o)(1+alphaT)...(ii)`
`2=(1+alphaT)/(1+2Talpha),(2+54alpha-1)/(alpha)=T,`
`(1)/(alpha)+54=T,(100000)/(105)+54=T,T=854^(@)C`
`thereforeT=854+273,T=1127K`


Discussion

No Comment Found

Related InterviewSolutions