1.

The temperature at which average kinetic energy of an atom in gaseous hydrogen becomes equal to the binding energy of the electron in hydrogen atom, is of the order of

Answer»

`10^(4)K`
`10^(5)K`
`10^(3)K`
`10^(2)K`

Solution :Since binding energy of the electron is 13.6eV and relation between temperature of gas and its AVERAGE molecular kinetic energy is `(3/2)KT =(1/2) mv^(2)`
Hence, `13.6eV =(3/2)Kt`
`T=(13.6 xx 1.6 xx 10^(-19)xx 2)/(3 xx 1.380 xx 10^(23)) approx 10^(5)K`


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