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The system that contains the maximum numbers of atoms is _______.(A) 4.25 g of NH3 (B) 8 g of O2 (C) 2 g of H2 (D) 4 g of He |
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Answer» Correct option: (C) 2 g of H2 Total number of atoms in molecule = n x NA x Atomicity Atomicity’s of NH3, O2, H2 and He molecules are 4, 2, 2 and 1 respectively. 17 g of NH3 = 4 x NA atoms ∴ 4.25 g of NH3 = \(\left(\cfrac{4.25}{17}\right)\) x 4 x NA = NA atoms 32 g of O2 = 2 x NA atoms ∴ 8 g of O2 = \(\cfrac{2\, \times \, 8}{32}\) x NA = \(\cfrac{N_A}{2}\) atoms 2 g of H2 = 2 x NA atoms = 2NA atoms 4 g of He = NA atoms Thus, the system that contains 2 g of H2 has maximum numbers of atoms. |
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