1.

The system of mass A and B shown in the figure is released from rest with x=0, determine the velocity of mass B when x=3m. Also find the maximum displacement of mass B.

Answer»

Solution :Constraint relation gives
`2sqrt(X^(2)+16)+y=c`
Differentiating w.r.t. time, we GET
`(dy)/(dt)= -(x)/(sqrt(x^(2)+dt))(dx)/(dt)`
Let `(dx)/(dt)=v=` velocity of `B`
`:. (dy)/(dt)=` velocity of `A=-(x)/(sqrt(x^(2)+16))v`
Minus sign indicates that it in upward direction.
`:.` Using energy conservation
`MG.3-(mg)/(sqrt(2)).2=(1)/(2)mv^(2)+(1)/(2)(m)/(sqrt(2))(v.(3)/(5))^(2)`
`RARR (3-sqrt(2))g=(v^(2)(25sqrt(2)+9))/(50sqrt(2))`
`rArr v=sqrt(((3-sqrt(2))(50sqrt(2)))/(25sqrt(2)+9))g=5 m//s`
Let `x_(1)` be the maximum displacement of `B`, then
`mgx_(1)-(mg)/(sqrt(2))2[sqrt(x_(1)^(2)+16)-4]=0`
`rArr x_(1)=8sqrt(2)m`.


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