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The system of linear equations 2x+2y-3z=1 4x+4y+z=2 6x+6y-z=3 has |
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Answer» Given : 2x+2Y-3z=1 4x+4y+z=2 6x+6y-z=3 To Find: Solution Solution: 2x+2y-3z=1 Eq1 4x+4y+z=2 Eq2 6x+6y-z=3 Eq3 2 * Eq1 - Eq2 => -7z = 0 => z = 0 3* Eq1 - Eq3 => -8z = 0 => z = 0 After substituting z = 0 2x + 2y = 1 4x + 4y = 2 => 2x + 2y = 1 6x + 6y = 3 => 2x + 2y = 1 Hence z = 0 and infinite solutions for x and y Infinite solutions and z = 0 Learn More: Show that system of EQUATION 3x-5y=11 and 6x-10y=20 is inconsistent for what VALUE of a, the pair if linear equation. ax+3y=a-3,12x+ay=a ... |
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