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The surface tension of soap solution is 0.03 N/m.What amount of work isrequired to produce a bubbleof radius 0.05 m ?O1.0002 J2.00003 JJO0.001884 JOnone of the above |
| Answer» NONE of the aboveExplanation:AnswerT=0.03Nm −1 r=0.05mW=2×T×4πr 2 =2×0.03×4π(0.05×0.05)=6π×10 −4 We GET, =6π×10 −4 | |