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The surface charge density of a thin charged disc of radius R is sigma. The value of the electric field at the centre of the disc (sigma)/(2 in_(0)). With respect to the field at the centre, the electric field along the axis at a distance R from the centre of the disc is |
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Answer» SOLUTION :The electric FIELD strength on the axis at a distance ..x.. from its centre of uniform charged circular disc is `E= (sigma)/(2 epsi_(0)) (1- (x)/((x^(2) + R^(2))^(1//2)))`. At centre, `E_(0) = (sigma)/(2 epsi_(0))` At distance `x= R, E = (sigma)/(2 epsi_(0)) (1-(x)/((x^(2) + R^(2))^(1//2)))= (sigma)/(2 epsi_(0)) (1- (R )/((R^(2) + R^(2))^(1//2)))` `=(sigma)/(2 epsi_(0)) (1- (1)/(sqrt2)) = (sigma)/(2 epsi_(0)) (0.37) = 0.37 E_(0)` |
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