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the sum of two digit number and the number obtained by reversing its digit is 176 find the number if its ten's place digit is greater than the units place digit by 2 |
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Answer» Answer:97 Step-by-step explanation: LET the UNIT's place be x. And TEN's place will be (x+2). Original number=10(x+2)+x =10x+20+x =11x+20 Reversed number=10(x)+x+2 =10x+x+2 =11x+2 11x+2+11x+20=176 22x+22=176 x+1=8 x=8-1 x=7 Therefore, original number =10(7+2)+7 =10*9+7 =90+7 =97 |
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