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The sum of two consecutive multiples of 17 is 391. find these multiples |
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Answer» Let the two CONSECUTIVE multiples be 17x and 17(x + 1) Given that SUM of two consecutive multiples is 391. = > 17x + 17x + 17 = 391 = > 34X + 17 = 391 = > 34x = 391 - 17 = > 34x = 374 = > x = 374/34 = > x = 11. Therefore, the REQUIRED numbers are: = > x = 17(11) = 187. = > 17(x + 1) = 17(11 + 1) = 204. Therefore, the required multiples are 187 and 204. Hope this HELPS! |
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