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The sum of three successive numbers in an ap is 192 then the numbers are |
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Answer» Answer: Step-by-step EXPLANATION: let THREE consecutive NUMBERS be a,a-d,a+d According to given condition.a+a-d+a+d = 18 3a= 18 a= 6 According to next given condition. a(a+d)(a-d) = 192 a(a-d)^2 = 192 (a-d)^2 = 32 a^2 +d^2 -2ad = 32 36 + d^2 - 12d = 32 d^2 -12d = -4 d^2 +d = 1/3.......(1) hope it HELPS you
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