The sum of three positive integers in AP is 24 and their product is 48

1.	The sum of three positive integers in AP is 24 and their product is 480 .find the numbers
Answer» Answer: Let the three terms be a-d,a,a+d Sum=24 Product=480 .°.a-d+a+a+d=24(d d CUT off) 3a=24 .°.a=8 (a-d)(a)(a+d)=480 (8-d)(8)(8+d)=480[.°.a=8] (8-d)(8+d)=60 $64 - d {2} = 60$ $d {2} = \sqrt{4} = 2$ If a=8,d=2 the terms are a-d=8-2=6,a=8,a+d=8+2=10 .°.The terms are 6,8,10. We will GET the same values if we'll consider d=-2 Step-by-step explanation: MARK as BRAINIEST $\ Deesha$

The sum of three positive integers in AP is 24 and their product is 480 .find the numbers

Answer»

Answer:

Let the three terms be a-d,a,a+d

Sum=24 Product=480

.°.a-d+a+a+d=24(d d CUT off)

3a=24

.°.a=8

(a-d)(a)(a+d)=480

(8-d)(8)(8+d)=480[.°.a=8]

(8-d)(8+d)=60

$64 - d {2} = 60$

$d {2} = \sqrt{4} = 2$

If a=8,d=2 the terms are

a-d=8-2=6,a=8,a+d=8+2=10

.°.The terms are 6,8,10.

We will GET the same values if we'll consider d=-2

Step-by-step explanation:

MARK as BRAINIEST

$\ Deesha$

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The sum of three positive integers in AP is 24 and their product is 480 .find the numbers​

Answer:

Let the three terms be a-d,a,a+d

Sum=24 Product=480

.°.a-d+a+a+d=24(d d CUT off)

3a=24

.°.a=8

(a-d)(a)(a+d)=480

(8-d)(8)(8+d)=480[.°.a=8]

(8-d)(8+d)=60

If a=8,d=2 the terms are

a-d=8-2=6,a=8,a+d=8+2=10

.°.The terms are 6,8,10.

We will GET the same values if we'll consider d=-2

Step-by-step explanation:

MARK as BRAINIEST

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No Comment Found

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The sum of three positive integers in AP is 24 and their product is 480 .find the numbers