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The sum of three numbers in AP is -3 and their product is 8 find the number |
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Answer» ong>Answer: Given INFO : the SUM of three numbers in arithmetic progression is -8 and the PRODUCT of these terms is 1. To find : the numbers solution : let (a - d), a and (a + d) are three terms in arithmetic progression. sum of three terms = . 8 → (a - d) + a + (a + d) = -8 + 3a = -8 → a = -8/3 New product of terms = 1 → (a - d)a(a + d) = 1 → (a° - ad?) = 1 →(-8/3) - (-8/3)d² = 1 →-512/27 + 8d2/3 = 1 =-512/27 + 8 d?/3 = 1 → 8d?/3 = 1+ 512/27 = 539/27 →d = tv(539/72) = ±2.74 therefore the numbers are ; - d = -8/3 - 2.74 = -5.406 a = -8/3 = -2.67 a +d = -8/3 + 2.74 = 0.073 = |
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