The sum of three no. in A.P. is -3 and their product is 8. Find the nu

1.	The sum of three no. in A.P. is -3 and their product is 8. Find the numbers
Answer» let the numbers be a-d,a,a+d sum= a+a+d+a-d= -3 3a= -3 a= -1 now PRODUCT, (a+d)(a-d)(a)=8 (a^2-d^2)a=8 (9-d^2)-3=8 d^2=9-8/3 d= under root19/3 HENCE the numbers are -1-under root19/3, -1 and -1+under root19/3

The sum of three no. in A.P. is -3 and their product is 8. Find the numbers

Answer»

let the numbers be a-d,a,a+d

sum= a+a+d+a-d= -3

3a= -3

a= -1

now PRODUCT, (a+d)(a-d)(a)=8

(a^2-d^2)*a=8

(9-d^2*)-3=8

d^2=9-8/3

d= under root19/3

HENCE the numbers are -1-under root19/3,

-1 and -1+under root19/3

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The sum of three no. in A.P. is -3 and their product is 8. Find the numbers

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