The sum of three consecutive terms of an ap is 30 their product is 360

1.	The sum of three consecutive terms of an ap is 30 their product is 360.find the terms
Answer» ☆ ΛПƧЩΣЯ ☆ Given: The sum of THREE CONSECUTIVE numbers — (a-d)+a+(a+d)=30 3a=30 a=10 The PRODUCT of three consecutive numbers are — $(a - d) \: a \:( a + d) = 360 \\ by \: substituting \: value \: of \: a \\ (10 - d) \: 10 \:(10 + d) = 360 \\ 100 - {d}^{2} = 360 \\ 100 - 36 = {d}^{2} \\ {d}^{2} = 64 \: \: \: \: ➞d = 8$ Hence the TERMS are 10,18,26.... ✈ 5 thanks ✈️ ➡️ Fo I l o w me ⬅️

The sum of three consecutive terms of an ap is 30 their product is 360.find the terms

Answer»

☆ ΛПƧЩΣЯ ☆

Given:

The sum of THREE CONSECUTIVE numbers —

(a-d)+a+(a+d)=30

3a=30

a=10

The PRODUCT of three consecutive numbers are —

$(a - d) \: a \:( a + d) = 360 \\ by \: substituting \: value \: of \: a \\ (10 - d) \: 10 \:(10 + d) = 360 \\ 100 - {d}^{2} = 360 \\ 100 - 36 = {d}^{2} \\ {d}^{2} = 64 \: \: \: \: ➞d = 8$

Hence the TERMS are 10,18,26....

✈ 5 thanks ✈️

➡️ Fo I l o w me ⬅️

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The sum of three consecutive terms of an ap is 30 their product is 360.find the terms​

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The sum of three consecutive terms of an ap is 30 their product is 360.find the terms