1.

The sum of three consecutive numbers in A.P. is 27,and their product is 504,find them.

Answer»

Hey

Here is your ANSWER,

Let the THREE NUMBERS be a-d , a ,a+d

a-d+a+a+d=27
3a=27
a=27/3
a=9

(a-d)a(a+d)=504
(a^2-d^2)a=504
(9^2-d^2)9=504
81-d^2 = 504/9
81-d^2= 56
-d^2 = 56-81
-d^2 = -25
d=+/-5

If d=+5
Terms = 4,9,14

If d=-5
Terms=14,9,4

Hope it helps you!


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